if you want to a train X starts at a at 4 pm and reaches B at 5 PM while another train y starts from B at 4 pm and reaches a at 5 30 pm at what time will the two trains cross all right so let's assume that the distance between A and B here a b, will denote that distance as D so train X starts from a and go to B, between 4 pm and 5 PM which means that it takes one hour for the train to travel from A to B, and we can denote the speed of that train being that it travels D kilometers per hour for trainx, train y start from B and goes to a and it's and it takes and it goes from 4 pm to 5 30 PM which means that it takes one and a half hours for train B to travel and for us to calculate the the speed of that train this is assuming that the trains are traveling at the constant speed by the way so to to calculate the speed of train y we need to do, distance divided by the time it takes which is one and a half hours which is the same as saying three divided by two, which you can also write as, two divided by 3 times D kilometers per hour so now that we have the speed the trains are traveling in we need to calculate the time it takes for trains to travel to a certain distance so let's let's call, T time okay so in order to calculate like how far a train travels in time we can do the first train try next and that's quite simple because it's it's just traveling, in a ratio is 101. so it's it's traveling and it's distance times t kilometers that's how far that that's how far the train X will travel in in time, the other train, it's it's similar things so it's the new value here two divided by three D times T is how many kilometers train y will travel at a certain time so one property of this problem too is that when the two trains cross they will both have traveled, the sum of the total distance and we can write that as equation that is, DT plus two divided by three DT equals D so now though now that we have the equation, we can solve for T just figure out when they mean so DT plus two divided by three DT equals D you can simplify this as writing it as five over three DT equals D to get rid of the five divided by three D we divide by that on both sides which gives us T equals D divided by five divided by three D, when you have the same numerator and denominator you can get rid of that which gives us d e t equals one divided by five divided by three, and this is the same as saying T equals three divided by five so now we have t and, 3 divided by five is 0.6 equals 0.6 so this is how many hours it takes it takes 0.6 hours for the two trains to meet and 0.6 if you want to get this in minutes you do 0.6 times 60 which is 36. 36 minutes so the two trains will meet, they started at 4 pm so the trains will meet at 4 36. P.M why do the mining nodes not align with